When an aqueous solution of borax is acidified with hydrochloric acid,a white crystalline solid is formed which is soapy to touch. Is this solid acidic or basic in nature? Explain.
(N/A) An aqueous solution of borax is acidified with $HCl$ to produce boric acid $(H_{3}BO_{3})$,which appears as a white crystalline solid and is soapy to the touch.
The chemical reaction is:
$Na_{2}B_{4}O_{7} + 2HCl + 5H_{2}O \rightarrow 2NaCl + 4H_{3}BO_{3}$
This solid is acidic in nature. Boric acid is a weak monobasic Lewis acid. It does not act as a protonic acid (it does not release $H^{+}$ ions directly); instead,it acts as a Lewis acid by accepting a lone pair of electrons from a hydroxyl ion $(OH^{-})$ from water:
$B(OH)_{3} + 2H_{2}O \rightarrow [B(OH)_{4}]^{-} + H_{3}O^{+}$
The chemical reaction is:
$Na_{2}B_{4}O_{7} + 2HCl + 5H_{2}O \rightarrow 2NaCl + 4H_{3}BO_{3}$
This solid is acidic in nature. Boric acid is a weak monobasic Lewis acid. It does not act as a protonic acid (it does not release $H^{+}$ ions directly); instead,it acts as a Lewis acid by accepting a lone pair of electrons from a hydroxyl ion $(OH^{-})$ from water:
$B(OH)_{3} + 2H_{2}O \rightarrow [B(OH)_{4}]^{-} + H_{3}O^{+}$
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Given below are the statements about diborane.
$(a)$ Diborane is prepared by the oxidation of $NaBH_{4}$ with $I_{2}$.
$(b)$ Each boron atom is in $sp^{2}$ hybridized state.
$(c)$ Diborane has one bridged $3$ centre$-2-$electron bond.
$(d)$ Diborane is a planar molecule.
The option with correct statement$(s)$ is :
$(a)$ Diborane is prepared by the oxidation of $NaBH_{4}$ with $I_{2}$.
$(b)$ Each boron atom is in $sp^{2}$ hybridized state.
$(c)$ Diborane has one bridged $3$ centre$-2-$electron bond.
$(d)$ Diborane is a planar molecule.
The option with correct statement$(s)$ is :
DifficultJEE MAIN 2021
View SolutionBoron forms covalent compounds due to:
Medium
View SolutionThe incorrect statement from the following is:
The correct orders among the following are
$A$. Atomic radius $: B < Al < Ga < In < Tl$
$B$. Electronegativity $: Al < Ga < In < Tl < B$
$C$. Density $: Tl < In < Ga < Al < B$
$D$. $1^{st}$ Ionisation Energy $: In < Al < Ga < Tl < B$
Choose the correct answer from the options given below $:$
$A$. Atomic radius $: B < Al < Ga < In < Tl$
$B$. Electronegativity $: Al < Ga < In < Tl < B$
$C$. Density $: Tl < In < Ga < Al < B$
$D$. $1^{st}$ Ionisation Energy $: In < Al < Ga < Tl < B$
Choose the correct answer from the options given below $:$
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